a 2mev proton (mass=1.6 *10^-27 kg) is moving perpendicular to a uniform magnetic field of 2.5 t.

vackrider

a 2mev proton (mass=1.6 *10^-27 kg) is moving perpendicular to a uniform magnetic field of 2.5 t. the magnetic force on the proton , give the complete solution

Shrey Choudhary

U sure..nothing else is given?

Harpreet aka MAX

First of all find the velocity from the given energy of the proton using

1/2mv² = Energy given

then Force on proton is give by = q. (v x B)

= qvB as angle btw velocity and magnetic field is 90

q = e and find the answweer

good luck

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