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Magnetism

Lokesh $ardana's Avatar
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19 Dec 2007 18:54:52 IST
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A.C.
None

If the peak value of current through inductor(L),
 
capacitor(C), resistor(R) in parallel A.C. circuit are
 
2 mA, 3 mA, 5 mA resp. Then find the peak value
 
of current delivered by the source in the same
 
circuit? 


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abc xyz's Avatar

Blazing goIITian

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19 Dec 2007 18:59:29 IST
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lol, aits pt 2.
Lokesh $ardana's Avatar

Blazing goIITian

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19 Dec 2007 19:05:07 IST
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yeah! it's from fiitjee's aits pt2
Lokesh $ardana's Avatar

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19 Dec 2007 20:30:01 IST
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someone please help yaar!!
Tarin Bansal's Avatar

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19 Dec 2007 20:49:00 IST
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Abe is question mai kya hai? Do it by phasors.
Dekh parellel mai the voltage on all 3 of them is same. SO we make current phasors.
Inductor- +ve y axis
Capacitor- -ve y axis
resistor- +ve x axis
Now find the net current just as you find net force i.e.,
I = [(2-3)^2 + 5^2]^1/2
= sqrt 26
Tarin Bansal's Avatar

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19 Dec 2007 20:50:02 IST
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Hehehe
Daadi wale bachche ne kar diya question. Agar samajh mai aaya ho to guru dakshina zaroor dena BABY RAMDEV ko.
Lokesh $ardana's Avatar

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19 Dec 2007 21:46:49 IST
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can you explain in detail using sine equations ????????

aur current ke liye phasors ka use??????????? woh bhi jab parallel mein ?????

dude,m getting in more confusion..............

maine to abhi tak sirf yahi padha hai ki phasors ka use sirf nett impedance ke liye karte hain......

and there is no question in HCV in which these 3 are in parallel in an A.C circuit...............

man! I m getting mad....

can anybody explain this concept in more details???????
Lokesh $ardana's Avatar

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19 Dec 2007 21:56:11 IST
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20 pts to that person who will explain this whole concept in a satisfactory manner...........
boredom's Avatar

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19 Dec 2007 21:58:42 IST
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Hey,
chill........
 
Use vector equation hence
                                         L =2                                          
                                              R=5
                                              C=3
[ ((12)+(5)2))  =   26
Lokesh $ardana's Avatar

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19 Dec 2007 22:03:06 IST
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ab ye kya hai?????????
dun u think u r giving same solution as given by tarin oooppppsss BABY RAMDEV.........

heheheheh....
boredom's Avatar

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19 Dec 2007 22:12:25 IST
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Hey,
Sorry, i thought you needed  pictorial representation(trust me it is boring to draw diagrams from the symbols given)he he......
if you need the explanation
since for inductor voltage leads current by pi/2
             capacitor voltage lags by pi/2
             resistor it is the same
hence the diagram
Ps: If you could say what you didnt understand......
Tarin Bansal's Avatar

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19 Dec 2007 22:27:20 IST
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Abe yaar to ''phasor'' naam sun ke dar gaya hai lagta hai. Phasor kuch nahi bas ek tareeka hai un quantities ko graphically represent karne ka jo alag alag phase mai hain. It is not necessary ki it is used to calculate impedance. It can be used everywhere.
See the basic idea is that behaviour of current & voltage in L,C,R remains same whether they R in series or parellel. Series parellel to bas current OR voltage distribution effect karte hain. They can't effect an inductor's or a capacitor's basic behaviour i.e., current lags in C, current leads in L.
Now in parellel, voltage on each L,C,R remains same so it is of no use.Here current varies. To humne iske phasors bana liye and we solved them like we simple add or subtract some forces along X and Y axes.
Jahan tak HCV ki baat hai usme AC bahut kam de rakha hai and questions are very easy and their are some mistakes also in the questions.

Samajh gaya kaise kiya yeh question?
BABY RAMDEV apni guru dakshina ka intezaar karega.
Hehehe
Rahul's Avatar

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19 Dec 2007 22:37:51 IST
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BABY RAMDEV ne bilkul sahi solve kiya hai. but if u want in sine eqns (lil long) u can do it by considering the instantaneous current.
Tarin Bansal's Avatar

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19 Dec 2007 22:50:19 IST
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Dhanyavaad.
Rahul's Avatar

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19 Dec 2007 22:50:46 IST
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let current thru R, I=5sinwt
E=5Rsinwt
u can equate peak voltage, 5R=3/wC=2wL
apply loop law across C
q=CV
i=dq/dt=CdV/dt = 3coswt (on solving)
apply loop law across L
-Ldi/dt=E=5Rsinwt
i=-2coswt (on solving)
net current = 5sinwt+coswt = rt(26)sin(wt+@)
hence peak current= rt(26)mA
Rahul's Avatar

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19 Dec 2007 22:52:22 IST
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BABY KO PRANAAM!!
Tarin Bansal's Avatar

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19 Dec 2007 22:57:40 IST
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PRANAM SWEEKAR KIYA JAATA HAI.

Hehehehe
Lokesh $ardana's Avatar

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19 Dec 2007 23:08:43 IST
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that's what I was asking .........thanks rahul ........and as per my promise I have given you 20 pts...........15 in this forum and 5 in an another post.......

and also BABY RAMDEV has also been rated..................

cheers!!!!!!!!
Lokesh $ardana's Avatar

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19 Dec 2007 23:14:40 IST
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and here is guru dakshina 4 baby ramdev.....
 
hehehehe...
Tarin Bansal's Avatar

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19 Dec 2007 23:19:53 IST
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MOORAKH VYAKTI. BABY RAMDEV NE TERI MUSIBAT HAL KI AUR TU BAS USE EK DOODH KI BOTTLE DE RAHA HAI. DEKH LI TERI SHRADDHA. JAA TUJHE SHAAP DETA HOON KI YEH DOODH TUJHE HI PEENA PADE AUR USKE BAAD TUJHE BOTTLE BHI KHAANI PADEGI. CHHOOOOOO.


Hehehehe



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