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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jun 2008 22:30:46 IST
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A charged particle is accelerated through a potential difference of 12kV and acquires a speed of  .It is then injected perpendicularly into a magnetic field of strength  .Find the radius of the circle described by it.
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25 Jun 2008 22:38:38 IST
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r = mv / qb
substitute and find the radius
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25 Jun 2008 22:41:12 IST
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we have
potential x charge=kinetic energy
12x 10^3 x 1.6 x 10^-19=1/2mv^2
frm here u get v
now use
r=mv/qb
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even a stopped clock is right twice a day |
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25 Jun 2008 22:42:05 IST
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v=velocity, V=potential.
Now, qV=1/2 mv2
So, mv = 2qV/v -----(1)
Now, Radius(R) = mv/qb
Putting the value of mv from eq (1), we get
R= 2qV/vqB = 2V/vB.
U know all these values i.e., v,V,B. Put it in the formula to get the answer.
Hope this helps you.
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25 Jun 2008 22:44:17 IST
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use
QV=1/2mv2
using dis find out m/Q'
u know velocity
put it in the equation
R=mv/QB
~cheers
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25 Jun 2008 22:45:23 IST
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@pink_ele,
It is not given in the question that the charged particle is an electron or a proton. Its just a charged particle. SO u CANT take its charge = 1.6 x 10^-19.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
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Posts:
Can marks really judge a student??
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25 Jun 2008 22:46:10 IST
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qV= 1/2mv^2
m/q=24*10^-9
r=mv/bq
=24*10^-9 *10^6/.2
=.12 m
= 12 cm
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25 Jun 2008 22:48:23 IST
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Arre yaar, why u all r taking q=1.6 x 10^-19???
It is NOT given in the question that the charged particle is an electron or a proton.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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25 Jun 2008 22:50:36 IST
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By the formula, R = 2V/vB, I am getting R= 12 cm.
Is it correct??
Although by deriving that formula and by taking the particle to be a proton/electron, we are getting same answers but I think the electron/proton method is wrong becoz its not mentioned in the question.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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25 Jun 2008 22:54:40 IST
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@ tarinbansal formul derived is r=2V/bv
on solving this we get r=0.12m=12cm(ans
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25 Jun 2008 22:56:36 IST
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Ya. I know we get this answer. I have written it in previous post. :-|
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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