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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: A charged particle is projected in a magnetic field of (7i-3j)x10 ^-3 T.
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juana (44)

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The acceleration of the particle was found to be ti+7j. Find t.

    
juana (44)

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does no one know?
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ramyani (2610)

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Simple.


Accln is along force ( magnetic ) F.


F is perpendicular to both v and B.  [ F = q ( V X B ) ]


so Accln a is perpendicular to B.


so         a.B = 0 


( ti+7j.) . ( (7i-3j)x10 ^-3 ) = 0


( t + 7 j ) . ( 7 - 3 )  = 0


7 t   - 21 = 0


 hence   t = 3


Rate me if it helps.


it is not important where u stand, but in which direction u are moving
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juana (44)

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yes i got your point but the answer is -3.
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tarinbansal (3903)

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No, the answer cant be = -3.
It is +3.

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vikkycoolboy (233)

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yeah the answer cant be -3!!


B.TECH ECE
NIT ALLAHABAD
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paddy.dude (1154)

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@ juana



what are u saying man.....how can time taken be negative

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tarinbansal (3903)

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@paddy.dude,

The 't' in the question doesnt denote time. 't' is a variable having units of acceleration.

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juana (44)

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hey t is an arbitary variable; it does not denote time here.
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paddy.dude (1154)

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sorry my mistake
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mukulaish (238)

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in the ques it shud b ti-7j to get t=-3.....

or evn in the magnetic field it shud b 7i+3j
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