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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2007 23:52:27 IST
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Q: An Inductance of 1H And resistance of 1ohm are connected in series with an alternating source of emf 200 volts and frequency 50 Hz . The time lag between voltage and current will be ?
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The more I learn the more I get to know, the more I know the more I forget, the more I forget the less I know, so why should I be learning??
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6 Apr 2007 00:43:41 IST
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is d answer 0.005...??????
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6 Apr 2007 00:53:09 IST
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hey the answer is .0005 . BUT HOW?
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The more I learn the more I get to know, the more I know the more I forget, the more I forget the less I know, so why should I be learning??
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
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6 Apr 2007 00:57:46 IST
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first find tan (theta) =XL/R....so t comes out to b 100pie....therefore theta is arc tan 100pie...which is approx 90 degree...
therefore since 2pie phase difference corresponds to time lag T hence pie/2 phase diff corresponds to time lag of 0.005.........where am i wrong.......?????? plz temme...
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6 Apr 2007 14:36:47 IST
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The phase lag  is given by tan = XL/R
tan = wL/R = 2 fL/R = 100
Hence time lag is given by :
t = (/2)T (T = time period)
t = [{tan-1(100)}/2](1/50)
This is approx. t = 1/200 = 0.005 sec
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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6 Apr 2007 20:20:05 IST
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Solution Provided explains all
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Bhupesh.M |
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