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25 Jun 2010 08:23:30 IST

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An electron is projected horizontally with a kinetic energy 5 keV in a space where the magnetic fiel

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An electron is projected horizontally with a kinetic energy 5 keV in a space where the magnetic field of strength 10-5 T exists in vertically upward direction. Calculate the sideways deflection of electron as it travels through 1 m along the direction of field.

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Killer Kiran

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25 Jun 2010 08:41:06 IST

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I wont solve it for you but I will give you the overall procedure.. 1) Get the velocity from the Kinetic energy 2) Calculate Radius 3) From simple geometry .. get the sideways deflection.. If you don't get the simple geometry part.. try again :)

silent killer

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25 Jun 2010 08:43:32 IST

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may i know wat the sideways diflection is?

please show it through the diagram so that i can try it......

Harsh Gurung

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29 Jun 2010 08:08:09 IST

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please give the simple geometry

manuraj

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2 Jul 2010 13:09:01 IST

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this ques is from HCV i think

edison

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27 Jul 2010 14:42:45 IST

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Motions of a charged particle in magnetic field

Motions of a charged particle in magnetic field (mm1b.gif)

Figure 1: Motions of a charged particle in magnetic field

Using F = q (v X B) = q v B Sin 90

or F = 1.6 * 10^-19 * v*10^-5

Now energy of electron = 5keV

Thus E = 1/2 m v²

or v = (2E / m )^1/2

where mass m = 1.67 * 10^-27 kg

or v = 978817 m/s

acceleration = a = F/ m = 1.6 * 10^-19 * v*10^-5/m

substitute m and v

and find displacement for 1m distance travelled along the intial direction of electron.

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