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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: An electron moving in a circular orbit of radius r makes n rotations per second.
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juana (44)

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What is the magnitude of magnetic field produced at the centre of the circle described?

    
paddy.dude (1154)

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i= frequency x charge
ie i = n x e

now B at centre of a circle is given by

B = mew zero x i / 2 x r
so ans comes out to be

B = mew zero x n x e / 2 x r
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dhiraj1 (57)

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angular velocity =n *2pie = 2pie/t


current =e/t


b =moue not *i /r

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crazynishant (48)

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An electron moving in a fixed circular path can be considered similar to a circular coil carrying current (because current arises due to flow of charges)

Now in the above mentioned case let the electron of charge ?e? moving with a angular velocity ?v?. Thus time period of revolution of electron is t= angle covered/angular velocity.
Thus t={2*(pi)}/v

Thus current flowing in the assumed coil I = charge/time period of flow of charge
Thus I=e/t or e/ [{2*(pi)}/v]
Or I =e*v/{2*(pi)}

Now the magnetic field at the center of a current carrying coil can be given as
B= uo*I/{2*r}

Thus B= uo* e*v/{4* (pi)*r}

The angular velocity is related to the mentioned angular frequency as v=2*(pi)*n

Thus B=uo*e*2*(pi)*n/{4* (pi)*r}
Or B= uo*e*n/{2*r}

Substitute values and find answer


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Nishant Bhaskar
1st year BE(Hons)
Electronics & instrumentation
BITS Pilani
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crazynishant (48)

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An electron moving in a fixed circular path can be considered similar to a circular coil carrying current (because current arises due to flow of charges)

Now in the above mentioned case let the electron of charge ?e? moving with a angular velocity ?v?. Thus time period of revolution of electron is t= angle covered/angular velocity.
Thus t={2*(pi)}/v

Thus current flowing in the assumed coil I = charge/time period of flow of charge
Thus I=e/t or e/ [{2*(pi)}/v]
Or I =e*v/{2*(pi)}

Now the magnetic field at the center of a current carrying coil can be given as
B= uo*I/{2*r}

Thus B= uo* e*v/{4* (pi)*r}

The angular velocity is related to the mentioned angular frequency as v=2*(pi)*n

Thus B=uo*e*2*(pi)*n/{4* (pi)*r}
Or B= uo*e*n/{2*r}

Substitute values and find answer


Rate if found useful

Nishant Bhaskar
1st year BE(Hons)
Electronics & instrumentation
BITS Pilani
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