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Ask iit jee aieee pet cbse icse state board experts Expert Question: biot savarts law
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supriyasingh (0)

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please derive expression for biot savarts law with necessary explanation
    
edison (4394)

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The Biot-Savart law is a physical law with applications in electromagnetics and, more generally, it is also useful in numerous other applications of vector field analysis. As originally formulated, the law describes the magnetic field set up by a steady current density.
 Mathematically, the Biot-Savart law provides an inverse to the curl operation; the result is unique up to gauge transformation. As such it has numerous additional applications.
The Biot-Savart law is fundamental to magnetostatics just as Coulomb's law is to electrostatics. The Biot-Savart law follows from the Lorentz transformations of the electric field of a point-like electric charge, which results in a magnetic field, and is fully consistent with Ampère's law, much as Coulomb's law is consistent with Gauss' law.
In particular, if we define a differential element of current
I dmathbf{l}
then the corresponding differential element of magnetic field is
dmathbf{B} = K_m rac{I dmathbf{l} 	imes mathbf{hat r}}{r^2}
where
K_m = rac{mu_0}{4pi} ,, where ?0 is the magnetic constant
Imathbf{} is the current, measured in amperes
dmathbf{l} is the differential length vector of the current element
mathbf{hat r} is the unit displacement vector from the current element to the field point and
rmathbf{} is the distance from the current element to the field point

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edison (4394)

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the derivation part is avilable in any standrd txt or ref. book for class 12. so above i have presented the law only

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supriyasingh (0)

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THANKS A LOT SIR
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