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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2008 19:11:12 IST
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18,19,20 pg 5-92
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2008 19:19:31 IST
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solve only 18, 19th n 20th solved
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18. let the amperian loop have a radius of xcurrent through the amperian loop = I * x^2/r^2 B(2pi x) =mu * I * x^2/r^2 hence B is proportional to x the last option will not be true because magnetic field is zero at infinity also
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science-
the most fundamental
the most eternal
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2008 20:30:56 IST
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wrong, ans is not (a)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2008 21:19:16 IST
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please reply quick ans is c
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2008 21:41:39 IST
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Hey ! the answer is (c) this is bcoz the wire is thin walled. so, for x<r, there is no current. hence, B=0. I hope u hav understood ! pls rate if useful !!!
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2008 21:46:12 IST
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thin walled, so why B =0? n i hv rated u
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2008 21:52:18 IST
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c yaar ! if it was a solid conductor, then why would they write thin walled ??? thin walled means it is a hollow cylindrical wire. so, for x<r, there is no wire ! hence no current and no B I hope u hav understood now ! if no, then ask me !
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2008 21:54:42 IST
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yup understood thanks
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2008 21:57:25 IST
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thanx for the rates ?? r u appearing for JEE 2008 ???
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Umang |
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