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Magnetism
if a charged particle goes unaccelerated in a region containing electric n magnetic fields,a > E must be perpendicular to Bb > v must be perpendicular to Ec > v must be perpendicular to B]d > e must be equal to vBdo explain ur answer...THNX
Comments (9)
SEE..
according to me....condition will be all 3 vectors shd be perpendicular to each other
like , x y z axis ...
now taking question ..suppose DUE TO E ..the force acting on particle
= qE ...in x direction positive ,,
so to balance the force force in negative dirn is provided by magnetic field force..
this is possible if B and v are perpendicular to each other and E as well ...
so all shd be perpendicular...hence a b and c are correct....
and qE = qVB ..
SO , E = VB....d is also correct




....a and b are correct ...bt they are jst part of full answer..









Ok.....i m not sure i can give the correct option here...but it sure i will give u the correct method....because option are somewhat confusing....ny how..
1.The thing is that particle is going unaccelerated.Means there should not be existence of only electric feild..because If only E is prsesnt then ofcourse particle will be accelerated whatever be the direction E have..and force will be q.E.
2.Now in presesnce of only B particle can be move without accelerating..how?..if the velocity will be parallel or anti parallel to B....because in this case force will be 0..{ F= q.B.v.sin@...and in case v||B then @ is 0 or pi}..No other direction gives uniform motion to charge.
3.One case is also possible.....when there exist E and B both...This is very unique case..Hoe can be possible in this case? lets see.
If B is perpendicular to v then force is equal to B.q.v....This force can be balance by force of E which is equal to q.E
q.E = B.q.v
or E = B.v
One condition is also E is perpendicular to B and V.
Now check ur option....i get only last one..which is also incomplete option...u must say that E perpendicular to B and v