IIT JEE , AIEEE Forum - Physics , Magnetism - Magnetic Effect of electric current !!!! HCV QUESTION.....

Driftkingnitish

pg 250 and 251

q.10

q. 19......... 4 this i aint getting the answer zero............ B gets added in same direction.......

pls tell it wont even take u geniuses 30 sec,,,.... reply soon and get rated......

heavensablaze

i will try out the 10 question

Firstly the formula for a field due to long straight wire is 2i/r X10^-7T

Now field due to the first and the second wire is 2X10^-7X10/2X10^-2T each.

Observe that angle between the resultant and individual field will be 60degree

Therefore the resultant will be [(2X10^-7X10/2X10^-2)²+(2X10^-7X10/2X10^-2)²+(2X10^-7X10/2X10^-2)²cos60]^1/2

It turns out to be 1.732 X10^-7T

Plz correct me if i am wrong.

tarinbansal

Q19- I think U must be dividing the current as i/2 and i/2. That's wrong.
The current will be divided as 3i/4(thru side AB) and i/4(thru the rest of the square). This is becoz while distrubuting current, its obvious to suppose that wire has some resistance and resistance in part ADCB is thrice of the resistance in the part AB. So current will get divided accordingly.
Now, the mag. field in downwards and upwards direction is equal and U get net field = 0.

Hope U get it.

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