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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Feb 2007 12:48:30 IST
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The magnetic fields on both sides of an infinite current carrying surface are given by B1 and B2 respectively.Find the pressure on the surface.(here i mean B1 & B2 in vectorial notation.i.e.,B1 bar and B2 bar)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Feb 2007 20:26:55 IST
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What do you mean by pressure. On what if it is wire we need the surface area of the wire
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Mar 2007 15:27:34 IST
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let us consider the sheet to b carrying a current in +ve z direction and lying along z-y plane with current per unit length(along y axis be W.L b the length of sheet along z axis. then
F =B1wdyL-BWdyL
P=(B1-B2)w
so whats the ans.
rate me if i m correct.
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keep it up!!!!!!!!!11 |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Mar 2007 15:29:42 IST
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here B! and B2 must b parell to the sheet.
i had used F=BiL
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Consider the sheet to be lying in yz plane and current is flowing along +z axis. The net field in the neighourhood of sheet will be have field because of sheet Bs and field because of other factors Bo. On one side of sheet field will be Bo+Bs and on other it will be Bo-Bs (Direction of Bs will be opposite on both sides) Putting Bo+Bs = B1 and Bo-Bs= B2 Bo=(B1+B2)/2 (Here additions are vector additions) Bs = mu*J/2 (where J is currect density)=(B1-B2)/2
Now consider a unit thin sheet of length l and width w.
It carries a current Jw and hence force on that piece is F=iBl=JBo*lw so pressure is JBo=(1/2mu)*(B1-B2)*(B+B2)
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Mar 2007 22:36:23 IST
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thank u sir
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