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10 Jan 2008 12:24:40 IST

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narrow beam of singly charged carbon ions , moving at a constant velocity of 6*10m/s,is s

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narrow beam of singly charged carbon ions , moving at a constant velocity of 6*10m/s,is sent perpendiculary in a rectangular region having uniform magnetic field b=0.5T. it is found that two beams emerge frm the field in the backward direction ,the separations are 3cm and 3.5 cm.identify the isotopes present in the ion beam . take the mass of an ion=A(charge of an electron)kg,where A is the mass number

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Pratyush Pande

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Joined: 2 Jan 2008

Posts: 58

11 Jan 2008 09:23:54 IST

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see the basic concept in the ques is that the isotopes have diff masses so the would have different radii while moving in the magnetic field...the ques tells about thier distance from the org beam after they udergo a deflection of 180⁰ and come out of the field.....so the distance b/w the org beam and the two beams are the diameter of the circles they had undergone motions in....

mv²/r = Bqv

r = mv/Bq

solving for first beam....

0.03/2 = A(1.6x10^-27)x6x10⁴/0.5x1.6x10^-19

A₁ = 12.5

solving for the second one similarly A₂ = 14.5833

these two answer can be rounded of to 14 and 12

Note - the mass of ion should be A(mass of proton ) and not what u have written in the ques

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