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Magnetism
Please solve, In a decaying L-R circuit, the time after which energy stored in the inductor reduces to one forth of its initial value is?
energy at time t=0
1/2Li2 and at time t=t enrgy is 1/4*1/2Li2 therefore i2=1/2
1/2=ie-tR/L
solving it we get the answer
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energy at time t=0
1/2Li2 and at time t=t enrgy is 1/4*1/2Li2 therefore i2=1/2
1/2=ie-tR/L
solving it we get the answer