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kane (2179)

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a charge Q is spread uniformly over an insulated ring of radius R.what is the magnetic moment of the ring if it is rotated with an angular velocity  w.r.t to normal axis?


answer is 1/2 QR2


there are numerous options besides I.I.T

<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>









    
Mr.IITIAN007 (2985)

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yeah its true ...and its +ve only if the rotation is done anticlockwise . Otherwise ....if its done clockwise ...then - ve charge accumulates at the centre and +ve charge accumulates at the rim ....thereby manking the rim be at a higher potential than that of the cetre . In that case the moment will be -ve .

Ken
From: UNITED STATES, Green Bay, Wisconsin
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kane (2179)

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i want the proof bro


there are numerous options besides I.I.T

<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>









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feynmann (2093)

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magnetic moment = i X A


i = Q/ T = Q w/2pi


A = pi R^2


so magnetic moment = 1/2 Q w R^2

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