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Magnetism

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8 Jan 2010 22:09:38 IST

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abhishek sinha

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14 Jan 2010 18:17:41 IST

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mean square value of current = 1/tao int (0 to tao) io^2 t^2/tao^2 dt = io^2/3

so rms= io/root(3)

Yagyadutt Mishra

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Joined: 19 Feb 2009

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14 Jan 2010 18:28:21 IST

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Correct answer!!!!!!!!!!

I = i(t/T)

rms...from the word it is clear that you have to find root of means square value....

If x is the quantity then mean square of this value is integeration of x^2 over the period where it is defined..divided by the time....

similarly means square value of I is equal to 1/T *int (I)^2.dt and limit is from o to T...

so you get mean square of I = i^2/3

Root mean square of I or rms of I = i/root(3)

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