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magiclko (4210)

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A Large spherical shell(radius r, charge q) rotating with angular velocity  is placed in gravity-free space, having uniform magnetic field, suc that its direction is perpendicular to the axis of rotation. If the mass of shell is "m", find the maximum kinetic enrgy of the shell.

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krish (146)

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Mass is given and angular velocity is also given....so apply that in any body , in equilibrium , the charge experiencing both centrepetal and magnetic force will be such that the forces r equal and opposite ....from this u get velocity of sphere.....maximum kinetic energy is mv*v/2
if i am wrong please reply.....

Krishnan
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magiclko (4210)

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I want the full solution and answer...

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The kinetic energy remains constant because the magnetic force cannot change the speed of the charged particle. It can only change the direction of the charge motion.
Let us divide the shell into rings of radius x whose distance from the center of the sphere is given by y and the thickness dy. Let the charge on the ring be dq, where dq is given by
dq = s 2p x dy. The current in this part of the ring is given by   di = dq w / 2p. The torque acting on the ring will be dt = di ( p x2 B). Therefore the total torque acting on the ring will be
t = ò di ( p x2 B) = ò s 2p x  w p x2 B dy / 2p = ò s  x  w p x2 B  dy = ò s w p x3 B  dy
Now for the relation between x and y.
R2 = x2 + y2 , from this eliminating x and integrating y between -r and +r we get the resultant torque.
But this torque will produce new rotation of the sphere and the therefore the torque value will change in such a way that the kinetic energy will remain constant always.
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magiclko (4210)

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so is the answer  1/2 I2  +  B, where  is the magnetic moment of the sphere....

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