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[Post New]12 Mar 2008 21:27:51 IST
    Subject: Try this - EMI
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karthik2007 (3375)

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refer figure

A conducting cross bar of mass m and length L can slide without friction up or down on two conducting rails. The rails are connected on the bottom via a variable resistance R and battery E, so that the rails and the bar form a rectangular conducting loop. A uniform magnetic field B points into the plane of the loop. Initially the bar is at rest. What is the total force acting on the bar, moving up at speed v?


I am not able to get the book answer, so please solve it.

Will nip in at times to solve problems :)
    
[Post New]12 Mar 2008 21:38:35 IST
    Subject: Re:Try this - EMI
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newarnav (218)

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"moving up at speed v"
"total force "
iff v is constant than Ans. is Zero(obviously yar)
if it is not than give how it is changing with time or displacement ..
My name is Arnav.
AIR 7041 IIT-JEE 08 got nothin,
currently in MA NIT bhopal civil...
still ..Hoping we'll meet in IIT next year !
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[Post New]12 Mar 2008 21:49:49 IST
    Subject: Re:Try this - EMI
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newarnav (218)

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am I right ?
My name is Arnav.
AIR 7041 IIT-JEE 08 got nothin,
currently in MA NIT bhopal civil...
still ..Hoping we'll meet in IIT next year !
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[Post New]12 Mar 2008 21:59:31 IST
    Subject: Re:Try this - EMI
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newarnav (218)

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hallo
koi he kya ?
 
My name is Arnav.
AIR 7041 IIT-JEE 08 got nothin,
currently in MA NIT bhopal civil...
still ..Hoping we'll meet in IIT next year !
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[Post New]12 Mar 2008 22:21:09 IST
    Subject: Re:Try this - EMI
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elastiboysai (2327)

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mg+ or - Bl(E-BlV)/R
dependin on wether motional emf > or < E
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[Post New]12 Mar 2008 22:22:09 IST
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karthik2007 (3375)

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all answers are wrong!
Will nip in at times to solve problems :)
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[Post New]12 Mar 2008 22:22:35 IST
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karthik2007 (3375)

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And I've typed the exact question here. So don't ask for clarifications
Will nip in at times to solve problems :)
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[Post New]12 Mar 2008 22:26:05 IST
    Subject: Re:Try this - EMI
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newarnav (218)

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F = ma
a= 0
F=0
what is wrong?
My name is Arnav.
AIR 7041 IIT-JEE 08 got nothin,
currently in MA NIT bhopal civil...
still ..Hoping we'll meet in IIT next year !
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[Post New]12 Mar 2008 22:29:30 IST
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karthik2007 (3375)

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It isn't given that it moves with a constant velocity v my dear. Please note that it starts from rest!!!
Will nip in at times to solve problems :)
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[Post New]12 Mar 2008 22:35:39 IST
    Subject: Re:Try this - EMI
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raulrag009 (1205)

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Is \;the\; answer\\\\ (\frac{BEl-Rmg}{R})
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[Post New]12 Mar 2008 22:38:13 IST
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karthik2007 (3375)

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Nope raul. The answer is independent of R
Will nip in at times to solve problems :)
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[Post New]12 Mar 2008 22:38:42 IST
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karthik2007 (3375)

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Moreover, this is from an AIEEE sample paper. This fact is pissing me off even further!
Will nip in at times to solve problems :)
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[Post New]12 Mar 2008 22:53:31 IST
    Subject: Re:Try this - EMI
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newarnav (218)

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book ka naam?
 
My name is Arnav.
AIR 7041 IIT-JEE 08 got nothin,
currently in MA NIT bhopal civil...
still ..Hoping we'll meet in IIT next year !
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[Post New]13 Mar 2008 02:32:24 IST
    Subject: Re:Try this - EMI
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shubham_sachdeva (1876)

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BEL/R - mg- BLv
 
 
without R u cann't find current...plzz post the answer written in the buk..!
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[Post New]16 Mar 2008 12:08:19 IST
    Subject: Re:Try this - EMI
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bsgdabest (169)

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i got it varying with time as mge-kt where k= B2l2/mR
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