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Magnetism

Blazing goIITian

Joined:	5 Dec 2007
Post:	704

9 Jan 2008 21:51:13 IST

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a charged particle of mass m n charge q is accelerated through a potential difference of V volts it enters a region of uniform magnetic field which is directed perpendicular 2 d direction of motion of particle d particle will move on a circular path of radius given by ? ans: rt[2Vm/q] * [1/B]

a particle of debroglie wavelength 2.21 *10^[-13] n charge 1.6 *10^[-19]c is projected with a speed 2*10 [6] m/s at an angle 60 2 d x axis if a uniform magnetic field of 0.3T is applied along d yaxis d path of d particle is ans: a helix of radius 0.03m n time period 6.25 [pie] 10^[-8] sec

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NITESH BASKARAN

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Joined: 29 Sep 2007

Posts: 487

9 Jan 2008 22:36:40 IST

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work done on charged particle = qV
K.E=qV
1/2mv^2=qV
v^2=2qV/m
v=rt(2qV/m)
mv^2/R=Bqv
R=mv/Bq
=rt[2Vm/q] * [1/B]

govind sukumaran

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Joined: 17 Mar 2007

Posts: 104

9 Jan 2008 22:46:18 IST

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YUP ANS TO SECOND ONE IS A HELIX.....coz the horizontal component of velocity( horizontal to B) will remain unchanged but the vertical component will provide it a centripetal accl and it will follow the path of a helix......simply replace the v in formula with vsin0

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