Home » Ask & Discuss » Physics
« Back to Discussion

Mechanics

Cool goIITian

Joined:	23 Jan 2007
Post:	34

28 Jan 2007 20:18:01 IST

0 People liked this

660

2 ask

Engineering Entrance , Medical Entrance , AIPMT , JEE Main , AIIMS , JEE Advanced , Physics , Mechanics

A centripetal force of 5.74 N is required to keep an object in a circular orbit. What is the mass of this object if it is traveling with a constant speed of 6.64 m/s and the radius of the path is 6.22 m?

	2.68 kg
	5.37 kg
	0.80 kg
	0.26 kg
	2.22 kg

Comments (2)

Anshuman Johri

Blazing goIITian

Joined: 27 Jan 2007

Posts: 559

28 Jan 2007 20:23:14 IST

Like 0 people liked this

F=mv²/r

therefore,

5.74=m*(6.64)²/6.22

m=0.809 kg

Gautam sharma

Cool goIITian

Joined: 25 Jan 2007

Posts: 30

28 Jan 2007 20:38:12 IST

Like 0 people liked this

i think the ans given by anshu is correct

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team