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Mechanics

Cool goIITian

 Joined: 23 Jan 2007 Post: 34
28 Jan 2007 20:18:01 IST
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Engineering Entrance , Medical Entrance , AIPMT , JEE Main , AIIMS , JEE Advanced , Physics , Mechanics

 A centripetal force of 5.74 N is required to keep an object in a circular orbit. What is the mass of this object if it is traveling with a constant speed of 6.64 m/s and the radius of the path is 6.22 m?
 2.68 kg 5.37 kg 0.80 kg 0.26 kg 2.22 kg

Blazing goIITian

Joined: 27 Jan 2007
Posts: 559
28 Jan 2007 20:23:14 IST
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F=mv2/r

therefore,
5.74=m*(6.64)2/6.22
m=0.809 kg

Cool goIITian

Joined: 25 Jan 2007
Posts: 30
28 Jan 2007 20:38:12 IST
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i think the ans given by anshu is correct

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