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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: A conceptual doubt.
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PRAM0D (98)

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A sphere of radius 'r' has an initial angular velocity 'w' and its  at a height 'h' above the ground at t = o. If its allowed to fall freely, the velocity just before it strikes the ground  = ?


is it  (2g(h-r))^1/2 or (2g(h-r))^1/2 + rw sin(t),  't' defined with respect to the y - axis?? I think its the latter but still I have a doubt.

    
varun.tinkle (1158)

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IT CAN BE THE FORST ONE ALSO
ASSUMING THE ROTATIONAL ENERGY DOES NOT CHANGE
MG(H-r)=1/2MV^2^2=2G(H-R)

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Renewed shall be blade that's broken
The crown less again shall be king.

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snail (133)

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If u are considering the centre of the sphere the first answer has to be correct.


The second answer can be correct if u are considering a rotating point on the surface of sphere at the level of centre provided the angular velocity is in vertical plain. It should be sin(wt) not sin t. In this case we have to add both velocities vectorially.


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animal (610)

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yes i also think that the ans could be the 2nd one bcoz with the translational motion of the sphere it also has initial ang vel which will also give it some vel


tell me if i m correct?


 

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suyashasthana (0)

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1st one...

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animal (610)

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can u explain how it is possible????????

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