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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Feb 2007 13:51:15 IST
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consider a vehicle going on a horizontal road towards east.Neglect any force by the air.The frictional forces on the vehicle by the road
(A) is towards east if the vehicle is accelerating
(B)is 0 if the vehicle is moving with uniform velocity
(C)must be towards east
(D)must be towards west
please give me the answer with proper explanation.
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13 Feb 2007 14:01:35 IST
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ANSWERS WILL BE A AND B . IF YOU DRAW FBD OF VEHICLE THE FORCES ACTING ON THE BODY WILL BE
1COROILIS FORCE
2CENTRIFUGAL FORCE
3NOAMAL REACTION
4GRAVITATIONAL FORCE
IF THE VEHICLE IS MOVING ALONG EQUATOR THEN ALL THESE FORCES WILL BE IN THE VERTICAL DIRECTION AND ONLY FORCE IN HORIZONTAL DIRECTION WILL BE FRICTION FORCE.IF VEHICAL IS ACCLERATING THEN FRICTION WILL PROVIDE THAT ACC.IF IT IS MOVING WITH CONSTANT SPEED THEN NO FRICTION REQIURED.
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13 Feb 2007 15:26:24 IST
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u have answered the question according to the concept of circular motion but the body is moving on he straight horizontal road ??
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14 Feb 2007 13:22:41 IST
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when a car moves the tyres rotate in the direction opposite to the direction of the movement of the car. think!!!!! so as the tyres move a frictional force acts which is opposite to its motion and in the direction of the movement of the car. so the frictional force acts in the direction of the motion of the car and provides the necessary acceleration.and whan it is movin with constant velocity the frictional force is zero as told by manish. i think u got my point.
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14 Feb 2007 14:34:04 IST
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I have a small controversy.... Do u think that the frictional force will be absent when the body is moving with constant velocity???????? Please tell me if I m wrong kghedriu
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15 Feb 2007 13:00:21 IST
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ya,i think its impossible to move with constant velocity provided friction is there. the car has to apply a certain amount of force to balance the frictional force so as to move with constant velocity. that's why problems with constant velocity are ended by a statement " NEGLECT FRICTION".
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