A small body is thrown at an angle to the horizontal with the initial velocity  . Neglecting air drag, find

a) the displacement of the body as a function of time.

b) the mean velocity average over the first  t  seconds

c) mean velocity averaged over the total time of motion.

i found the first part ......

dont forget to rate me if correct

dude..i got just the same answer. but its not matching and its frm irodov and irodov generally doesnt make mistakes. The answer is vt + gt^2 / 2.

Yeah both Irodov and sarvesh.iit_m are right . The point is that Irodov takes Vo and g to be vectors and gives the answer in vector form. Whereas sarvesh gives it in the natural scalar form .

the formula s = vt +1/2 gt^2 is valid in vector form also .

ok..let it be in vector form. but shouldnt it be s = vt - 1/2 gt^2 ??? just because its vectors doesnt mean that directions of acceleration must change right?