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22 Oct 2009 19:50:35 IST

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A point moves with deceleration along the circle of radius R so that at any moment of time its tange

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A point moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal om moduli. At the initial momemt t=0, the velocity of the point is equal to v. Find: a) the velocity of the point as a function of time and as function of the distance covered s b) the total acceleration of the point as a function of velocity and the distance covered.

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VARUN RAJ

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Joined: 16 Mar 2008

Posts: 1825

22 Oct 2009 21:40:09 IST

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ignoring the modulus sign

dv/dt=v^2/r

dv/v^2=dt/r

or -1/v=t/r

now intwgrating beween v(x) and v and from t=0 and t=t we get v

now we got v as a function of t now we use ds/dt to get s as a function of t now substitute the values to get v as a function of s

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