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Blazing goIITian

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13 Jul 2009 16:34:16 IST

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a small block of mass m is kept at the left end of a larger block of mass M and length L. the syste

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a small block of mass m is kept at the left end of a larger block of mass M and length L. the system can slide on a horizontal road.the system is started towards right with with an initial velocity v.the friction coefficient between road and bigger block is n1. and that between the blocks is n2. (n2

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Comments (14)

aal izz well

Blazing goIITian

Joined: 6 Jun 2009

Posts: 409

13 Jul 2009 17:25:34 IST

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koi plz.. thoda sa kasht karke....explain kar do mere mechanics ke questions

Suraj

Cool goIITian

Joined: 25 Jun 2009

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13 Jul 2009 17:29:26 IST

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aap agar kripaya thoda kasht karke ye bataye ki prashn kya hai

aal izz well

Blazing goIITian

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13 Jul 2009 17:34:43 IST

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ok..continued.....

(n2<n1)........ find the time elapsed.....before the smaller block separates frm bigger block..

now answetr kasht karke

aal izz well

Blazing goIITian

Joined: 6 Jun 2009

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13 Jul 2009 17:34:44 IST

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ok..continued.....

(n2<n1)........ find the time elapsed.....before the smaller block separates frm bigger block..

now answetr kasht karke

~Áß???????

Blazing goIITian

Joined: 31 Aug 2008

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13 Jul 2009 17:40:06 IST

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see here u mean smaller block on bigger block on left corner naa..?

aal izz well

Blazing goIITian

Joined: 6 Jun 2009

Posts: 409

13 Jul 2009 17:41:07 IST

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yes!

~Áß???????

Blazing goIITian

Joined: 31 Aug 2008

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13 Jul 2009 17:46:38 IST

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wait trying..!

BALGANESH

Blazing goIITian

Joined: 21 Dec 2007

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13 Jul 2009 18:03:10 IST

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a small block of mass m is kept at the left end of a larger block of mass M and length L. the syste

~Áß???????

Blazing goIITian

Joined: 31 Aug 2008

Posts: 982

13 Jul 2009 18:08:26 IST

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NOW here /.

as smaller block be ,mass = m

and bigger block = M ...length of M block = L

now seeing FBD ..due to friction both the block hv some jerk ..

see ..let M moving forward with accn = a2

and m with a1 ...due to jerk (pseudo force.)

now a1> a2 ..so that the ....block get disconnected ..

hence now for m block

S( m ) = vt + 1/2 a1 t^2

S (M) = vt + 1/2 a2 t^2

now as block m moves L distance more so .

vt + 1/2a1 t^2 = vt + 1/2 a2 t^2 + L.........................................(1) => a1t^2 = a2t^2 + L

now considering frictiona force and FBD of both blocks ..

for block m ....eqn

m a1 + n1mg = 0

hence ma1 =-- n1mg

and for bigger block ..M eqn

M a2 + n2 ( m + M ) g - n1 mg = 0

a2 = ( n1 - n2 ) mg + n2 Mg / M

so now we hav a2 and a1 ...both ..

putting values in ..eqn we get value of t

i hope u can getthat value on ur own..!

BEST OF LUCK..

~Áß???????

Blazing goIITian

Joined: 31 Aug 2008

Posts: 982

13 Jul 2009 18:13:37 IST

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maybe i hv interchanged n1 and n2 symbol ..as given in ques..

in ma ques n1 is for m block and n2 for M block.

~Áß???????

Blazing goIITian

Joined: 31 Aug 2008

Posts: 982

13 Jul 2009 18:22:55 IST

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now see this diagram and undersatnd equations .

HERE ....FORCE WITH BLUE COLOUR ARE ON m BLOCK

AND FORCE WITH GREEN COLOUR ARE ON M BLOCK ..

AND OTHERS INFO GIVEN IN QUESTION .

f1 = frictiobal force on m

and f2 frictional force on M ..

~Áß???????

Blazing goIITian

Joined: 31 Aug 2008

Posts: 982

13 Jul 2009 18:26:46 IST

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and yes navjot ..dude ..is ur doubt clear??

aal izz well

Blazing goIITian

Joined: 6 Jun 2009

Posts: 409

13 Jul 2009 18:41:34 IST

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hey abhi... u approved of balganesh's answer but his answer is wrong...

the correct answer is .....

[(2ML/(M+m)(n1-n2)g)]^1/2

~Áß???????

Blazing goIITian

Joined: 31 Aug 2008

Posts: 982

13 Jul 2009 18:49:04 IST

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u CHK MA ANSWER AFTER SOLVING ITS SAME I THINK..!

yup ....its same as given by u ..!i think..!( and don`t rate till u satisfied with answr i future..!

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