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piyush shukla's Avatar
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24 Apr 2009 13:49:19 IST
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a train is running at a constant acceleration. the two ends of the train pass a telegraph post with
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a train is running at a constant acceleration. the two ends of the train pass a telegraph post with velocities v1 and v2.find the velocity with which the middle point of the train passes the same post.


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Akshay's Avatar

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24 Apr 2009 14:16:52 IST
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BALGANESH's Avatar

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24 Apr 2009 15:09:05 IST
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let the length of train be L

at this moment the train has velocity V1

after some time the rear part crosses teh same place with velocity V2

so initial velocity = V1

final velocity = V2

distance covered = L

V^2=u^2+2as

thus a =v2^2-v1^2/ 2L

now consider the middle part inital velocity = v1

distance covered = L/2

a=v2^2-v1^2/ 2L

V^2 = V1^2 + 2* (v2^2-v1^2/ 2L)*L/2

v^2 = V1^2 +V2^2 /2

Yagyadutt Mishra's Avatar

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24 Apr 2009 15:31:30 IST
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Yagyadutt Mishra's Avatar

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24 Apr 2009 15:32:02 IST
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Sagar Saxena's Avatar

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26 Apr 2009 14:58:47 IST
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yes the answer solved is correct


Blazing goIITian

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26 Apr 2009 22:03:07 IST
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Yagyadutt has done this very brilliantly...



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