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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2007 20:44:48 IST
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Two masses of equal magnitude m are lying on X-axis at (-a,0) and (a,0) respectively. They are connected by a light string and constrained to move only along X-axis. A force F is applied at the origin along Y-axis. The magnitude of the acceleration (in the X-direction) of each mass when the co-ordinates become (-x,0) and (x,0) is given by---------
Please try to help!
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15 Apr 2007 20:52:27 IST
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at any instant two equation will satisfy the eq are
2Tsin$=F.............(1)
and Tcos$=ma where $ is the angle which string will make with xaxis as we apply the force F the $ will also increase the acceleration will be a=Tcos$/m at any instant
obviously it is not constant and will decrease as time will pass
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15 Apr 2007 20:54:31 IST
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Can you please elaborate a bit more?
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15 Apr 2007 21:07:47 IST
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i can"t make i diagrame bcoz my mouse is not working i will give a complete solution till tomorrow after watching the diagrame the situation will become 100% clear in ur mind
good bye take care
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15 Apr 2007 21:13:38 IST
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Thanks a lot!
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15 Apr 2007 21:45:06 IST
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hey..let me try n explain this...we apply the force along y axis...the force acts on the 2 sides of the thread lyin on 2 sides of the origin with equal magnitude..so if we were to consider the components of the force along the 2 axes..the net force along x axis should end up 0...that along y is F..so take T to be tension on both the sides of the thread..
2Tsin$= F [tension along y addin up]
the forces along x cancel..
finally take component of the tension as defined above along x axis[direction of motion of the balls] and divide by mass fr acc...
sry if i confused u more than simplify it!!
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
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<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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29 Apr 2007 23:11:25 IST
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Good answer indian army
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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