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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Apr 2008 19:31:33 IST
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A wheel consists of a circular disc of radius a with four circular hole each with a radius of a/4. the center of a holes form a square and each center is at a distance of a/2 from the center of the disc .if m is the mass of the wheel after the holes have been punched in it what is the moment of inertia of the new wheel .
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we are the allies of konoha.....shinobis of the....sand
shubham sunder |
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22 Apr 2008 19:54:26 IST
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is the answer
123ma^2 / 256
m is the mass of the wheel
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22 Apr 2008 20:08:57 IST
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sorry bro...the correct answer is 55ma^2/96.....
the given m is the mass of the cut out wheel.....
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we are the allies of konoha.....shinobis of the....sand
shubham sunder |
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25 Apr 2008 16:46:15 IST
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c'mon goiitians....
reply soon....
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we are the allies of konoha.....shinobis of the....sand
shubham sunder |
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25 Apr 2008 16:58:14 IST
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what is the axis of rotation?
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25 Apr 2008 17:32:17 IST
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the axis must be the line passing through the centre and perpendicular to the plane...
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we are the allies of konoha.....shinobis of the....sand
shubham sunder |
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25 Apr 2008 17:42:04 IST
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ans is 55Ma^2/96
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25 Apr 2008 17:45:06 IST
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cal mass of disc if there was no hole. then calculate its MOI.
now cal mass of each small hole and MOI for each hole. now simply substact the MOI of whole ring and four times the MOI of one hole
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25 Apr 2008 22:34:21 IST
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i did exactly that but my ans didnt match......
could u please give the entire soln.
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we are the allies of konoha.....shinobis of the....sand
shubham sunder |
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