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deedee (1622)

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d take off speed of d plane is 80 km/hr......after a 100m long run
if d mass of d plane is 10 metric tons, & coefficient of static friction betwn d tyre & runway is 0.2
find d minimum force developed by d engine for take off
g =9.8
 
...........plz   solve...........in detail

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walk as if u dont care who rules d world

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kishan12 (309)

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See frictional force which has to overcome is
umg=0.2*10^4*9.8=19600
after this only plane starts moving...

Now V(final)=80km/hr=22.22m/s
V^2=2as
therefore a=2.4686
the force for this is F=ma=10^4 * 2.4686=24686
Add up the two
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deedee (1622)

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thank u

don't walk as if u rule d world
walk as if u dont care who rules d world

-this is knw as attitude


B who u r and say wat u feel ......
coz those who mind don't matter ........
and those who matter dont mind ......... :)


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