IIT JEE , AIEEE Forum - Physics , Mechanics

gaurav03

A packet is thrown from an aircraft , the path as seen from aeroplane is straight line.while the path seen by ground observer is parabolic.What is the actual path of the packet????

plz explain......how????????????

maverick83

Parabolic

iitkgp_bipin

You have yourself mentioned that the path as seen by ground observer is parabolic. So the actual path as seen from the ground is parabolic.

Omi

dude it depends on the frame of refrence.....wer u r..??? frm whch frme u seeing the packet...if u r wit the pilot the its a straight path...bt wen u r on the grnd its parabolic....or if u r on the packet...thn u r nt in motion u r at rest....it all depends upon the fancy word...FRAME OF REFRENCE.....juz in case if the examiner doesnt mention thn u can tke it for granted tat u r in the grnd frame....

IF U LIKE MY ANSWER PLZZZ RATE ME......!!!!!!

waterdemon

Inactual this isn't to be explained anyways here is some explanation.

As observed from the plane its path is a astraight line .

As observed from ground its path is a parabolic path.

Now suppose we take a frame of reference say XY plane , then we can

say that its path is parabolic( As XY plane is at its position irrespective of

packet's motion.

Hope you get it.

Cheers !!!!!!!!!!!!

b_srikalyan009

If you consider the initial velocity of the packet it is along the +x direction(say). this velocity is constant as there is no acceleration in that direction. only if plane is considered to move horizontally.

hence this will be a parabolic path with respect to ground.

but to the observer in plane, because the horizontal velocity of plane is considered constant, relative velocity in that direction is zero.

hence w.t.r plane the packet is moving freely under gravity.

hence it is straight line.

if u still have any doubt replz.

gomurali

The path is mentioned only with respect to some reference point. The path is parabolic with respect to an observer on the ground. It is st. line downwards w.r.t the pilot of the plane if the plane is moving with constant velocity. So path has meaning with respect to the reference point. It is not proper to say actual path with out mentioning the reference point

aspiringiitan17

ya thts ryt
the path observed depends upon the frame of refernce chosen for observation

prathyu

The path obeserved is only with the respect to reference point. the piolet sees it to be falling straight but the man standing below sees it to be moving parabolic. This is just because of air resistance upon the packet . i think u got me........

jatinroxx

The path depends on the FRAME OF REFERENCE.

When you are in the plane's frame of reference, the negative of the velocity of the plane is superimposed on the packet and hence it moves in a straight line.

In the ground frame of reference the packet has a horizontal velocity and acceleration in the downward direction and hence a parabolic path...

I hope u understood...

gomurali

pratyusha, it is not because of air resistance, it appears as parabolic. But it is due to two dimensional motion of the projectile. A projectile will have two dimensional motion. Both along x, and y axes. The combined motion makes it to move in parabolic path.

linkinsid_park

Actual path is parabola. Since the path seen by earth is parabola and earth is inertial frame of reference. since aircraft is also moving with the same horizontal velocity as the packet. therefore packet moves only in one dir. i.e; downwards.

sailesh_07

the packet has some intial velocity u in the x-dir, therefore according to Newton's first law of motion will continue to be in uniform if no force acts, since gravity acts on the packet, it moves forward as well as downward this path is a parabola, hope this satisfies u!!

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