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Mechanics

Blazing goIITian

Joined:	13 Dec 2006
Post:	666

22 Feb 2007 13:04:49 IST

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545

again gravitation

None

The orbital velocity of an artificial sattelite in a circular orbit just above the earth surface is 'v'. For a satellite orbiting at an altitude of half the earth's radius, the orbital velocity is

a. 3/2 v b.

(3/2) v

(2/3) v d. (2/3) v

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Kiran H

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Joined: 7 Nov 2006

Posts: 296

22 Feb 2007 13:58:27 IST

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V₀=

( G*M / R)

V₀^' =

( G*M/ (3R/2) )

V₀' / V₀ =

(2/3)

therefore

V₀' =

( 2/3) V₀ ,

Hence c) is the right answer.

Cheers!

Himanshu

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Joined: 19 Feb 2007

Posts: 3834

22 Feb 2007 14:16:53 IST

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Vo= (gR*2/R+h)*1/2

R=R h=R/2
now solve

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