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Mechanics

Blazing goIITian

Joined:	18 Feb 2007
Post:	1042

20 Apr 2008 21:23:00 IST

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432

AIEEE ques Plz Solve

None

After falling from rest through a distance y , a body of mass m begins to raise a body of mass M (M>m) that is connected to it by means of a light inextensible string passing over a fixed smooth pulley. Find the time it will take for the body of mass M to return to it's original position

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Comments (4)

Little_Master

Scorching goIITian

Joined: 19 Apr 2008

Posts: 268

21 Apr 2008 13:10:54 IST

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P.E of m = m g y

m g y = (M+m)v^2/2 (K.E of combined mass)

So v =

2mgy/m+M

v = u+gt

v = -v+gt

t = 2v/g

t = 2

2mgy/m+M

rate me if it's correct !!!

Priyesh

Blazing goIITian

Joined: 18 Feb 2007

Posts: 1042

21 Apr 2008 14:58:50 IST

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nopes u're wrong

ans . given is 2m/M-m root(2y/g)

joy francis

Blazing goIITian

Joined: 19 Feb 2007

Posts: 1802

21 Apr 2008 16:30:43 IST

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BALGANESH

Blazing goIITian

Joined: 21 Dec 2007

Posts: 1025

21 Apr 2008 16:42:10 IST

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something is wrong
how come M come back to its original position
mso M continues to falll till it reaches the table

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