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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 20:25:00 IST
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a particle performs uniform circular motion wid an angular momentum L .if the frequency of particles motion is doubled and its kinetic energy halved the angular momentum becomes??
ans L/4
plzz give the solution
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28 May 2008 20:31:31 IST
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L = I w
w =angular frequency
K. E . = 1/2 I w^2
I = 2 K.E. / w^2
L = 2 K .E. / w
w = 2 pi f
f = frequency
use the information given in the question
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