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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 00:54:18 IST
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net force on the body prforming circular motion (horizontal) is =0 true/false?
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konvicted |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 04:43:05 IST
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I think it's false, because a body performing a circular motion has an accelerated motion ( direction of its velocity changes at each point). and since the motion is accelerated the force will not b zero.
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Next ISSAC NEWTON....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 17:51:36 IST
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Force of course is not zero...for the above reason.... and that force is directed towards center in uniform circular motion ...
(but work done is 0 in uniform circular motion because motion is perpendicular to direction of force)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 17:51:58 IST
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iN ANY CIRCULAR MOTION SAY UNIFORM OR NON-UNIFORM THERE ALWAYS ACTS AN ACCELERATION & an acc can not act without any force so force will not be ZERO Yes if u r asking about the acc in horizontal or vertical direction then answer will depend upon the type of circular motion it is performing means it was travelling in horizontal circle ,vertical circle,etc I think now it will be clear to u
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Hey padio, Yes it's true that in the string, the tension will act & that's equal to the centripetal force acting. Here also there is a misconception. Just like action reaction pair, this is also one. The centripetal force acts on the body rotating, & to equalise that one , the tension force acts in the rope. Now, the point to note is that, the force would have been zero, if it would b acting on the same body.But, centripetal force is acting on the body & tension is acting in the string in opposite direction. U can also understand that by taking the case of breaking of string. If u rotate it extremely fast, at a point , the string will break. If the force would b zero, then it would have never broken.
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