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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2007 21:51:29 IST
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A man of mass 60 kg is standing on a light weighing machine kept in a box of mass 30kg. The box is hanging from a pulley fixed to the ceiling through a light rope, the other end of which is held by the man himself. If the manages to keep the box at rest, what is the weight shown by the machine? How much force should the man exert on the rope if he has to get the correct weight on the machine?
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15 Apr 2007 21:58:42 IST
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it shouid be 70N approx
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15 Apr 2007 22:00:11 IST
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no man...if u say sumthing...pls reason it
cheers!
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the forces on man will be tension in upward direction let it be T normal reaction by lift let it be N weight obviously downward tension upward N also upward
the equation of man is
mg=T+N............(1) m=60kg
after making FBD of box we will get this eq
Mg+N=T..........(2) obviously N will be downward on box T upward and weight downward
600=T+N...........(1.1)
300=T-N
solving we will get T=450 and N=150N as normal reaction is 150N so machine will show 15kg
thats it
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15 Apr 2007 22:18:19 IST
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i did a silly mistake in my previrious solution sorry for that
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15 Apr 2007 23:22:17 IST
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n the second part of the question?
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15 Apr 2007 23:43:06 IST
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is it 1800N
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18 Apr 2007 11:22:07 IST
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bah...how?!
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18 Apr 2007 12:40:27 IST
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HI I have already posted the whole solution of 2ND part in an another topic Lift-pulley problem plz watch solution there
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28 Jul 2007 13:27:06 IST
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can u giv me the link to that post?...ill surely rate u...
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