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deepesh28 (12)

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a conic pendulum ,athin uniform rod of lenth L and mass M,rotates uniformly about a vertical axis with angular velocity(w) the upper end of the rod is hinged .find the angle  b/w the rod and the vertical


 

    
neelesh_tripathi (0)

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plz. illustrate with a figure




if u think u can,u can if think you can't you're right
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shubham_sachdeva (1901)

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Tsin@= M.L/2sin@.w^2


Tcos@ = Mg


cos@= 2Mg/MLw2


= 2g/Lw^2


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deepesh28 (12)

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since it is a rod and not


 


the thread                      




 


 




 


with a pendulun




 






 




 


 




 






 




 


u cant use the concept of tension

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shubham_sachdeva (1901)

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who said it???


 




 


tell me the answer.


 




 


please read ur buk again


 


and see what is called


 


tension!!


padhna likhna chad de mitra , nakal te rakhi aas , chak chaddar te so ja bhagta , Rabb karega tennu paas.....

PLZ NEVER EVER RATE ME FOR MY ANSWERS , IF U WANT TO COMPLIMENT ME THEN JUST BEAT UR HEAD & SAY
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deepesh28 (12)

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ok then solve it ans is cos=3gl/2w^2 

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shubham_sachdeva (1901)

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hehehee..ur answer is dimensionally incorrect...check it again.

padhna likhna chad de mitra , nakal te rakhi aas , chak chaddar te so ja bhagta , Rabb karega tennu paas.....

PLZ NEVER EVER RATE ME FOR MY ANSWERS , IF U WANT TO COMPLIMENT ME THEN JUST BEAT UR HEAD & SAY
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PLZZZZZZ NEVER RATE ME....HOPE U WILL UNDERSTAND....

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sarvesh.iit_m (48)

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pl. rate if found useful




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shubham_sachdeva (1901)

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@sarvesh. :- x cos theta would be x sintheta see again.


padhna likhna chad de mitra , nakal te rakhi aas , chak chaddar te so ja bhagta , Rabb karega tennu paas.....

PLZ NEVER EVER RATE ME FOR MY ANSWERS , IF U WANT TO COMPLIMENT ME THEN JUST BEAT UR HEAD & SAY
"YEH KIS PAGAL NE MERA QN. SOLVE KER DIYA"

I AM SERIOUS!!!!
EVEN SERIOUS ^ INFINITY
PLZZZZZZ NEVER RATE ME....HOPE U WILL UNDERSTAND....

Shubham

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sarvesh.iit_m (48)

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sorry dude....


twas such a silly mistake.....


replace xcostheeta by xsintheeta and vice versa


to get answer in cos inverse instead of sin inverse

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