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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 13:51:16 IST
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as dy /dx is slope then wt is d^y/dx^2
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20 Mar 2008 13:53:08 IST
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rate of change of slope?
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20 Mar 2008 14:19:58 IST
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curvature
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Impossible To be Impossible is Impossible |
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20 Mar 2008 14:26:01 IST
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rate of change of slope....
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"I a universe of atoms.......an atom in the universe" |
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20 Mar 2008 14:47:47 IST
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it is rate of change of slope. For eg., in a displacement-time graph the slope dy/dx give the velocity while d^2y/dx^2 give you rate of change of velocity i.e. acceleration.
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20 Mar 2008 15:02:05 IST
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The significance of d^2y/dx^2 is that it gives an idea about the shappe of the curve which represent the function y = f(x).
If the value of d^2y/dx^2 at a pont is +ve it implies that the graph is curving further up (minima) and if it is _ve then it is curving down (maxima).
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