two bodies a and B r thrown upward simultaneously with the same speed.The mass of A is greater then that of B.Suppose the air resistance is equal for both of them and the air exert a force then
(a)The two bodies will reach the same height
(b)A will go higher than B
(C)B will go higher than A.
(D)none of these
but in this case in addition to gravitational force resistive force is also acting which is equal in magn. for both thus as the mass of A is greater therefore its accl. would be lesser than that of B in downward direction. thus A will go higher than B
v^2 - u^2 = 2as
v = 0 for both
u = same for both
a = -g forboth
therefore the height will be same for both when there is no resistance.
also as per we consider forces
since mass of a is larger so force given to A is larger ( but the velocity is same thus g make the same effect on both) also the force feel by A is larger. If we take effect of gravitational force in terms of speed then it will reduce the same as it reduce the speed of B. (due to difference in initial forces of A and B) so the effect on height is only due to initial velocity not by forces if we not consider the resistance.
But when we consider the resistance which is same for both A and B then
R = m * a
where a is retarding acceleration.
as mass of a is larger the retardation a is lesser so B will feel relatively more effect on velocity than a so A will go above than B.
Preparing for JEE?
Kickstart your preparation with new improved study material - Books & Online Test Series for JEE 2014/ 2015
@ INR 5,443/-
For Quick Info
Find Posts by Topics