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alisha_gupta_27 (10)

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5 kg block is pulled along a horizontal frictionless floor by a cord that exerts force=12 N at an angle of 25 degree above the horizontal.(a)what is the magnitude of block's acc?(b) force is slowly increased .What is its value just before the block is lifted (completely)off the floor(c)what is the magnitude of block's acc just before it is lifted (completely)off the floor?


    
elessar_iitkgp (2259)

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Mass of the block, m = 5 kg
Force applied, F = 12 N
Angle of application of force, = 25, with horizontal
(a) a = Fcos/m
    Substitute and evaluate the answer.
(b)In the vertical direction,
    N + Fsin = mg
    N = mg - Fsin
    Just at the moment of liftoff, N = 0
    F = mg/sin
    Substitute the values and find the answer
(c)Just before liftoff,
    A = Fcos/m = mgcos/msin = gcot



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