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Mechanics
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ramyani chakrabarty
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Joined: 22 Apr 2007
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14 Sep 2007 19:49:47 IST
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Both these sums were solved by elsser iit. search his messages abt 2 months ago.
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21 Sep 2007 17:23:45 IST
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for problem 28...i m denoting friction coeff. as u1 and u2...instead of amd ....
forces on M : grav. force= Mg (vertically down)
tension= 2T(two strings horizontal, one on pulley)
tension= T (vertically down due to string on pulley)
Normal reaction on M at lower surface= N (vertically up)
Normal reaction on M due to m= R (to the left)
Friction due to m on M =f1=u1. R (vertically down)(sliding is going on)
friction in M at lower surface= f2=u2. N (to the left) (sliding is going on)
net force on M vertically up :ZERO
to the right= MA
forces on m : grav force= mg (vertically down)
reaction due to M= R (to the right)
tension= T (vertically up)
friction due to M on m= f1=u1. R(vertically up)
net force on m to the right= mA
net force on m vertically down= ma
The unknowns are N,R,a,A,T,f1,f2,
write a constraint eqn for relating accns a and A.
and a=2A is to be derived from length of string method illustrated in example 6 in page 73 of HCV-1
solve them!!!!
try to do it yourself.... it will take a long long time to draw and explain .... try to understand....please......
forces on M : grav. force= Mg (vertically down)
tension= 2T(two strings horizontal, one on pulley)
tension= T (vertically down due to string on pulley)
Normal reaction on M at lower surface= N (vertically up)
Normal reaction on M due to m= R (to the left)
Friction due to m on M =f1=u1. R (vertically down)(sliding is going on)
friction in M at lower surface= f2=u2. N (to the left) (sliding is going on)
net force on M vertically up :ZERO
to the right= MA
forces on m : grav force= mg (vertically down)
reaction due to M= R (to the right)
tension= T (vertically up)
friction due to M on m= f1=u1. R(vertically up)
net force on m to the right= mA
net force on m vertically down= ma
The unknowns are N,R,a,A,T,f1,f2,
write a constraint eqn for relating accns a and A.
and a=2A is to be derived from length of string method illustrated in example 6 in page 73 of HCV-1
solve them!!!!
try to do it yourself.... it will take a long long time to draw and explain .... try to understand....please......











