IIT JEE , AIEEE Forum - Physics , Mechanics - CAN ANYONE SOLVETHE 14TH PROBLEM OF PG.268 IN D.C.PANDEY MECHANICS VOL.2?

karthik2007

Question please? I don't have dc pandey :)

ramyani

14TH PROBLEM OF PG.268 IN D.C.PANDEY MECHANICS VOL.2

Q. A cube is floating in liquid. Now temperature is increased. Considering the expansion of cube only :

{ Figure shows that a cube is floating in liquid. The vertical distance from the bottom of floating cube to liquid surface is x and vertical distance from the bottom of container of liquid to liquid surface is y }

A. both x and y will increase.
B. x will decrease while y will remain constant.
C.both x and y will decrease.
D.x will decrease while y will increase.

ramyani

And i spent some time in typin frm buk.

bvsatyaram

Here we need to consider only the expansion of block. (Forget abt the expansion of liquid.)
So, as the temp increases, the density of the block decreases but the weight remains the same.
The weight of the liquid displaced must be equal to the weight of the block. So, the same volume of liquid must be displaced even now. So, the volume of the block inside liquid remains same. Since, the area of cross section of the block increases due to heating, the depth (though with the block dips in water) must decrease to maintain constant volume of liquid displaced. So, x decreases. The height of liquid remain same. So, y must increase.

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