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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Dec 2007 17:46:13 IST
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Please help me!!!!!!
page 164
3 salutes for the correct answer
Sorry for not posting the question.....
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"I a universe of atoms.......an atom in the universe" |
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13 Dec 2007 17:59:23 IST
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Which problem there?
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Will nip in at times to solve problems :)
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13 Dec 2007 17:59:49 IST
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which problem
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13 Dec 2007 18:08:43 IST
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Please post the problem and the diagram if any. It is a pain getting the book everytime mate.
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Will nip in at times to solve problems :)
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13 Dec 2007 23:03:50 IST
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oops sorry
prob 61
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13 Dec 2007 23:18:00 IST
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Q] The smaller mass in the fig is pushed on the longer one at a speed v and the system is left to itself.
a] Find the speed of the larger block when the smaller block is sliding on the vertical part
b] Find the speed of the smaller mass when it breaks off the surface of the larger mass at a height h
c] Find the max height that the smaller block ascends(from the ground)
d] Find the distance traversed by the bigger block during the time when the smaller block was in its flight under gravity.
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"I a universe of atoms.......an atom in the universe" |
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13 Dec 2007 23:23:50 IST
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(a)
if V is the vel of big block towards left,
( M + m ) V = mv ( The smaller mass in the fig is pushed on the longer one at a speed v)
V = mv / ( M + m )
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it is not important where u stand, but in which direction u are moving |
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13 Dec 2007 23:31:41 IST
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The other parts??????
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"I a universe of atoms.......an atom in the universe" |
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13 Dec 2007 23:58:42 IST
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Conserve the mechanical energy to get the answer to the next part.
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14 Dec 2007 00:02:08 IST
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yes.
( B)
Let v1 be the vel at which the block breaks off.
Then,
intial energy of block = mv2 / 2
kinetic energy of large block = MV2 / 2
P.E. of small block = mgh
K.E still retained by small block = mv1 2 / 2
ppl. of consv. of energy gives,
mv1 2 / 2 + mgh = mv2 / 2 - MV2 / 2
v1 2 / 2 + gh = v2 / 2 - (M / m ) V2 / 2
v1 = desired result
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14 Dec 2007 00:09:40 IST
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After putin value of V from (a) in above, u gt reslt
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