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frenied (107)

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An aeroplane moves in a circle in the vertical plane with a velocity varying with its ht. h  from the lowermost level as v2=v02-2a0h.If  v0/2 is its velocity at highest point then find its accn. at the point where its velocity becomes vertical.......2 salutes for the correct ans....solution by tomorrow.
    
shubham_sachdeva (1865)

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can u attach a dia. qn. is sumwhat confusing....

padhna likhna chad de mitra , nakal te rakhi aas , chak chaddar te so ja bhagta , Rabb karega tennu paas.....

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frenied (107)

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sry pal no diag given
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frenied (107)

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think i missed sumthng earlier....try this now.
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shubham_sachdeva (1865)

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vel. at highest point = Vo/2
 
so applying energy of conservetion at instance , when it was at highest point & when its velocity is vertical(i.e at R(radius) distance above the lowermost point)
 
1/2 m . Vo^2/4 + 2mgR = 1/2 m v^2 + mgR.  ,where v is velocity at 2nd instance
 
from above we get
 
v^2 = Vo^2/4 + 2gR
 
now putting in eqn. we get
 
Vo^2/4 + 2gR = Vo^2 - 2aoR        ao = Ao
from above we get
 
Vo^2/R = radial accn. = 8(g - ao)/3

padhna likhna chad de mitra , nakal te rakhi aas , chak chaddar te so ja bhagta , Rabb karega tennu paas.....

PLZ NEVER EVER RATE ME FOR MY ANSWERS , IF U WANT TO COMPLIMENT ME THEN JUST BEAT UR HEAD & SAY
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I AM SERIOUS!!!!
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PLZZZZZZ NEVER RATE ME....HOPE U WILL UNDERSTAND....

Shubham

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frenied (107)

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sry thats incorrect....
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khushi210 (0)

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is it   10ao/3 ??
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rabindra8 (73)

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Horizontal component of velocity is constant in overall it's path and it is V0/2.
due to height change vertical componet of velocity is change all time in it's path  so the resultant velocity is change all time in it's path. velocity becomes vertical at two points and at that point  ' a =  {g2 + (5V02)/(8h) }1/2
At one point acc is +ve and other point acc is -ve.
this is  a good question.

I like to solve the tough problems, because nothing is tough.
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karthik2007 (3303)

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Is the acceleration

 = 100ao2/9 + g2



Will nip in at times to solve problems :)
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spideyunlimited (3007)

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Let max height = H
 
at max height if velocity is V
V2 = vo2 - 2aoH
H =  ( vo- V2  ) / 2ao
H = 3 vo / 8 ao
 
Velocity will be vertical when h = H/2
v2 = vo2 - 2a(H/2)
v2 = vo2 - 2ao . (vo / 16 ao)
v2 =  vo2 - (vo / 8)
v2 =  7 vo / 8
 
Now use given equation again
v2 = vo2 - 2aoh
ao = ( vo2 - v2 ) / 2h
ao = ( vo2 - (7 vo / 8)  ) / 2h
ao = ( vo / 8 ) / 2h
ao = vo/ 16 h

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karthik2007 (3303)

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Hmm... well I also got all the steps till the velocity, but do you think ao is being asked here? I was under the impression that ao is some crappy constant, though it dimensionally represents acceleration

Will nip in at times to solve problems :)
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spideyunlimited (3007)

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maybe. maybe not. lets see couldnt figure out anything else cos shubham's answer he said was wrong

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* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)






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karthik2007 (3303)

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Hmm... okay lets wait for freined's reply

Will nip in at times to solve problems :)
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frenied
... reply please

Will nip in at times to solve problems :)
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waterdemon (5135)

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