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Ask iit jee aieee pet cbse icse state board experts Expert Question: Change in KE=?
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tarinbansal (3574)

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Change in Kinetic energy=?
 
A- Work done by all the forces(internal+external+conservative+non conservative)
B- Work done by all the forces(internal+external+conservative)
C- Work done by all internal forces(conservative+non conservative)
D- Work done by all external forces(conservative+non conservative)
 
Answer as soon as possible. URGENT!!!
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rooney (889)

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[B] I think.

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nishantsingh89 (970)

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i think its A

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rooney (889)

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@nishant
http://www.batesville.k12.in.us/physics/PhyNet/Mechanics/Energy/stored_energy.htm

So, answer is not [a]  

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tarinbansal (3574)

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Rooney ,
the link you provided does not solve my problem.
It does not tells clearly why the answer is not (A).
Even I think the answer is (A).
Somebody please help.

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tarinbansal (3574)

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Rooney ,
the link you provided does not solve my problem.
It does not tells clearly why the answer is not (A).
Even I think the answer is (A).
Somebody please help.

The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.

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tarinbansal (3574)

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rooney (889)

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As you say when pushing a book, the work that you do "against friction" is apparently lost - it is certainly not available to the book as kinetic energy! Forces that do not store energy are called nonconservative or dissipative forces. Friction is a nonconservative force, and there are others. Any friction-type force, like air resistance, is a nonconservative force. The energy that it removes from the system is no longer available to the system for kinetic energy.



So, how is not clear that [A] is not the answer as it includes non-conservative forces

EDIT : Hmm well I thought about it. Consider you throw a block on a rough surface. So, initial kinetic energy is +ve. Friction acts on it and reduces K.E. to 0. So, there is change in K.E. So, answer could be [A]. I agree.

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tarinbansal (3574)

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My question is CHANGE IN KE .
For example when a block is slowly descending down an incline with friction, in that case the change in KE=0. It means that we have to consider the work done by friction also. Becoz if we consider the work done by mg only, than it would tend to increase the KE of the body. But as change in KE=0, it means that the work done by friction will aslo be considered.

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karthik2007 (3337)

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It should be A

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rooney (889)

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@tarin

yes, i edited the last reply

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krishna.gopal (2142)

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Its A only.
Rooney Let a body moving with velocity v is kept on floor with some friction. Its KE decreases. Its friction which is doing negative work on it.

In your example you are doing some positive work on the book while friction is doing some negative work on the book. If your fore is equal to frictional force then total work done on book is zero and hence there is no change in KE

Krishna Gopal Singh
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IIT Delhi 2002
Currently doing PhD from IIT Delhi
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rohitkuruvila (162)

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it will be d
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arpan_pointech (7)

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its (b) only conservative forces are taken into account
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