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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2007 23:35:17 IST
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The ratio of time taken to complete 1 revolution of two orbits of radii R and 4R.
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TECHNOLOGY IS MY WORLD.
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6 Apr 2007 10:41:06 IST
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T2  r3
so,
ratio is 1:8
rate reply if its correct
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6 Apr 2007 13:55:56 IST
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Kepler's Law :
T2  R3
(T1/T2)2 = (R1/R2)3 = (R/4R)3
(T1/T2) = (R/4R)3/2 = (1/4)3/2 = 1/8
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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6 Apr 2007 20:02:54 IST
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Solution provided Explains all
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Bhupesh.M |
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7 Apr 2007 00:14:35 IST
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GUYS IF ANGULAR VELOCITY IS SAME THEN THE RATIO WILL BE 1:1
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7 Apr 2007 02:55:30 IST
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on the other hand if velocity(speed) is same then ratio will be
2*3.14*R/2*3.14*4R=1:4
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7 Apr 2007 03:01:07 IST
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IF U R TAIKING ABOUT A ORBIT WHERE KEPLERS LAW CAN BE APPLIED LIKE PLANATERY MOTION OR MOTON OF A CHARGE AROUND AN ANOTHER CHARGE OF OPPOSITE SIGN THEN THE RATIO WILL COME 1:8 USING KEPLER'S LAW
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