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Mechanics

New kid on the Block

 Joined: 8 Sep 2012 Post: 2
8 Sep 2012 11:43:07 IST
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circular motion
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a metal ring of mass m and radius R is placed on a smooth horizontal table and is set rotating about its own axis in such a way that each part of the ring moves with a speed v. Find the tension in the ring.

New kid on the Block

Joined: 8 Sep 2012
Posts: 2
8 Sep 2012 13:50:18 IST
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T=(mRw^2)\2where radius=Rtake a small part(Rd@)on the ring and then draw its free body diagram.it will experience tension T from both the sides.since that park is moving in circul.equate the components of tension to mrw^2...then u will get 2T*sin@\2=dmRw^2where dm=mass of that part=mass per unit length*lenth of that part=[m/2pie*R]*R@*rw^2and u will finally get T=mrw^2\2

New kid on the Block

Joined: 8 Sep 2012
Posts: 2
8 Sep 2012 13:52:16 IST
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by @ i mean "theeta" and by ^,to the power.for ex.-3^2=3 to the power 2 i.e., 9.

Blazing goIITian

Joined: 4 Jan 2007
Posts: 489
11 Sep 2012 01:25:37 IST
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The tension in the ring must be

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