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Mechanics

Blazing goIITian

Joined:	18 Feb 2007
Post:	1042

23 Sep 2007 22:22:32 IST

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214

Circular Motion

None

A smooth wire of length 2

a bent into a vertical circle. A bead 'P' can slide smoothly on the wire. The circle is rotated about the vertical diameter as axes with a speed 'w' the bead P is at rest with respect to the circular ring in the position shown in the figure.Then ' w² ' is equal to

A) 2g / a B) 2g / a

3 C) 2g

3 / a D) 2a / g

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Comments (1)

Neeraj Agarwal

Blazing goIITian

Joined: 22 Jan 2007

Posts: 2039

23 Sep 2007 22:45:30 IST

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let angle between normal rxn.(N) at P makes angle x with horizontal...

then cosx=a/2/a =1/2 => x=60 [since normal rxn passes through center ]

N sinx =mg and Ncosx= mw^2 .(a/2) [since it rotates in a circle wid radius a/2]

so w^2 can easily be found...

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