IIT JEE , AIEEE Forum - Physics , Mechanics

sinjan.j

Two runners start simultaneously from the same point on a

circular 200-m track and run in same directions. One runs at a

constant speed of 6.20 m/s, and the other runs at a constant speed

of 5.50 m/s.

when will the fast one overtake the slower one?

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this may be an easy problem, but I am getting confused... as far as I have analyzed.. the distance traveled for overtaking is same and the time taken for overtaking is different....

If this is the correct analysis.. then I am not able to proceed further... can yiu help me to proceed??

Thanxx..!!!

sinjan.j

someone answer plzz

ADPDAVCTC

let A be the faster one & B b the slower one.....at the time of overtaking A covers greater distance than B but takes the same time....here the relative speed is 0.70m/s....iff the relative speed becomes large then distance taken by faster one to cross slower one becomes smalller.....since 0.70 is much smaller...so ans. wud be much greater than 200m....IS THE ANSWER "1771.23m"
TIME TAKEN BY REL.SPEED TO COVER 200m=200/0.70=285.7sec.
TIME TAKEN BY "A" TO COVER 200m=200/6.20=32.26sec.
therefore DISTANCE TAKEN IN JUST OVERTAKING "B"
=(285.7/ 32.26) x200 = 1771.23m
hoppp uu understand.....uuu r a blazing goiitian..........but i m just a new kid having ZERO votes &rates...........thanxxxxxxxxxxx

sriram.a

in a simple way 0.7t=200,t=200/0.7
distance=(200)(6.2)/0.7=1771.23

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