IIT JEE , AIEEE Forum - Physics , Mechanics - clarification of doubt regarding gravitational force of attraction

PANTHANGI

1. the ratio of two masses are 2 : 1 and these two masses reaches the ground simulteneously , the what is the ratio of their height from which they are dropped.

kindly reply at the earliest with clear explanations.

thanking you

yours sincerely

P.SUPRAJA

JR.INTER

HYDERABAD

nivedh_89

1:1.......is it correct

PANTHANGI

sorry sir, I could not understand the answer is achieved. kindly give a bit of clarity.

thanking u

yours sincerely

p.supraja

nivedh_89

is the answer correct????????????

bcas , as their u = 0,t = t and accelerations are also equal, their distance covered should b equal..........................!!!!!!!!!!!!!!!!!!!!!!!!!!!!

nivedh_89

whatever be the masses, unless if the masses are negligible, those masses willreach the ground at the same time if dropped from the same height at the same time.......................!!!!!!!!!!!!!!!!nudge me if u still didnt understand the concept.......n plzzzzzzz dont call me SIR..................

bhuvana89

well remember this point.....

2 falling bodies of different masses reach the earth in same time. two bodies of differnt volumes & same mass
will not reach simultaneously. body of smaller volume will reach earlier bcoz upthrust on
smaller volume < upthrust in larger volume.......

hope this clarifies ur doubt.....

spideyunlimited

acceleration g does not depend on mass of the body when theyre neglibile compared to mass of earth.

thus if they reach ground at same time, the height from which theyre dropped is same. so ratio is 1:1.
s = ut + 1/2 a t^2

acceleration is independent of mass. it is force which depends on mass.

tushar.vaidya

yes hi's right.whate be the masses of bodies the rate of falling will be allways same.sinc there is no consideration of mass in kinematics formulas.............
s=ut+1/2at^2
where s=h, u=0
i.e. h=-1/2t^2
considering both bodies, &falls scimultaneously,they'll take same time to fallsince rate f falling is same.
therefore for body of mass ratio 2,,,,,,,,,,
h1= -1/2gt^2......(1)
for ody of mass ratio 1,,,,,,,,,,,,,,,,,
h2= -1/2gt^2......(2)
from 1&2
h1=h2
therefore ratio of h1&h2 will be 1/1

iitkgp_bipin

If the masses of the objects are very small as compared to that of the earth then the acceleration for both of them will be same = g.
Since they are dropped their initial velocities are 0.

h = (1/2)gt²

Since g and t for both are same, so the heights will also be same.

h₁ = h₂

Actually it does not depends on the ratio of masses because acceleration for both of them are same.

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