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joyfrancis (1504)

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Q) Two waves of equal amplitude A and equal frequency travel in the same direction in a medium. the amplitude of the resultant wave is
1) 0
2) A
3) 2A
4) between 0 and 2A
 
Q) Two waves represented by y=asin(t-Kx) and y=acos(t-Kx) are superimposed ; the resultant wave will have amplitude
a) a
b) a2
c) 2a
d) 0
 
Q) The wave equation y=Asin2(kx-t) represents a wave motion with
Amplitude=.......
frequency=.......

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punitcooldude (124)

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the answer to the first one is 4) bcoz these waves can undergo constructive or destructive interference depending on their phase diff,.

2) y=acos(t - kx)  y = asin(t - kx + /2)
    As the phase difference b/w the 2 waves is /2, treat thier amplitudes at a pt. as vectors with /2 angle b/w them. By principle of superposition, we add these vectors to get the resultant amplitude which comes out to be a 2.

3)u can do this graphically, plot the graph of this function to get a wave
   u would see its amplitude is A  and  frequency is 2n where
n= /2

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abhijeet_0201 (756)

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punit your ans for 3rd ques is wrong

its A/2.
bec sin^2(kx-wt)=(1-cos2(kx-wt))/2
so the eq becomes y=(A/2)(1-cos2(kx-wt))
so amp=A/2

also
T=2pie/w n=w/(2pie)
here w=2w (y=(A/2)(1-cos(2kx-2wt))
n=w/pie
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punitcooldude (124)

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thnx for correcting me abhijeet.

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abhijeet_0201 (756)

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u r welcome!!!!!!!
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punitcooldude (124)

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abhijeet could u answer my ques. on pan balance in mechanics section?

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